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author:
ŠKORPÍK, Jiří (LinkedIn.com/in/jiri-skorpik)
issue date:
September 2022, November 2024 (2nd ed.)
title:
Internal losses of turbomachines and their influence on turbomachine design
proceedings:
provenance: Brno (Czech Republic)
email: skorpik.jiri@email.cz
Copyright©Jiří Škorpík, 2022-2024 |
Essential concepts for description of internal losses in turbomachinesThe internal losses Lw as the difference between the ideal work and the actual work of the machine are always caused by some transformation or transfer of energy in the individual parts of the machine with different intensity. Apart from profile losses, other types of internal losses also occur, for example, through leakages, friction between the working fluid and the casing and shaft, etc. The calculation of internal losses is done within a single stage (internal stage losses) or the whole machine (internal machine losses), etc.
![]() 1: Internal losses Lw [J·kg-1] internal losses in machine part under investigation; Lx [J·kg-1] value of individual loss in machine part under investigation. x-identification of investigated type of loss.
![]() 2: ξx [1] loss coefficient of individual loss; wid [J·kg-1] ideal work of working fluid; wi [J·kg-1] internal work of working fluid.
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Secondary flow lossIn real blade passages, there are losses due to secondary fluid flows respectively fluid flowing outside the required directions. For axial stages, these secondary flows are mainly passage vortices, for radial stages it is the opposite circulation.
![]() 3: Main pressure gradient in blade passage (a) formation of pressure gradient in blade passage; (b) formation of transverse flow due to different pressures, resp. their gradients between core c and foot h and tip t. SS-suction side of blade; PS-pressure side of blade; PV-passage vortices; CV-counter vortices. p [Pa] pressure; W [m·s-1] relative velocity of working fluid. r-radial direction; θ-tangential direction; a-axial direction. |
![]() 4: Example of bowed-twisted blade (3D stacks)
![]() 5: V [m·s-1] absolute velocity; r [m] radius; wE [J·kg-1] Euler work on investigated radius; ω [rad·s-1] angular velocity of rotor rotation; a, n [SI] proposed constants; b [SI] constant (can be calculated from proposed Euler work on reference radius). |
![]() 6: Tangential velocity component profile along length of bowed-twisted blade (a) r·Vθ=const.; (b) Vθ profile according to Equation 5 (n<-1).
Formation of opposite circulation in stage with radial velocity componentThe opposite circulation (or relative eddy) is caused by the action of the Coriolis acceleration on the flowing working fluid in the radial direction, therefore this circulation has a more significant effect the larger the radial component of the flow. It significantly affects the flow in radial stages, see Figure 8a. This phenomenon is analogous to cyclones forming in the Earth's atmosphere.
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![]() 8: Opposite circulation in radial stages (a) direction of opposite circulation; (b) centripetal flow; (c) centrifugal flow. Ω [rad·s-1] angular velocity of opposite circulation; ar [m·s-2] centrifugal acceleration; ac [m·s-2] Coriolis acceleration.
![]() 9: ΔWθ [m·s-1] deviation of tangential component of relative velocity at rotor outlet caused by opposite circulation.
![]() 10: Definition of slip coefficient of radial cetripetal turbines (a) effect of opposite circulation on flow; (b) in case of centripetal turbines it is possible to compensate slip by changing angle of absolute velocity in front of rotor, thus changing angle of relative velocity; (c) general formula for slip coefficient; (d) special formula for slip coefficient at β1∞=90° (other cases, for example, in [Dixon and Hall, 2010, p. 279]). μ [1] slip coefficient for centripetal turbines; β [°] relative velocity angle. V-vortices that arise during flow separation from blades. The index ∞ denotes the parameters of the velocity triangle for the case of an infinite number of blades (the case where no opposite circulation arises). |
![]() 11: Slip coefficient of centrifugal stages of working machines μ [1] slip coefficient for centrifugal stages of working machines (formulas for its calculation are given, for example, in [Dixon and Hall, 2010, p. 239]). Tip clearance lossesTip clearance losses is the negative effect of the overflow of the working fluid at the blade tips from the pressure side to the suction side, which also causes counter vortices, see Figure 12. ![]() 12: Overflow of working fluid over edges of blades and formation of counter vortices at tips
Tip leakage lossesThere must be a radial gap δ between the rotor blades and the casing, respectively between the stator blades and the shaft, even if shrouds are used, see Figure 13. The working fluid that leaks through this gap does not do any work and therefore represents a loss. The value of this loss depends on the design of the stage and the shroud. |
![]() 13: Tip leakage losses (a) leakage in case of impulse stage with disc type rotor and blades with shrouds; (b) loss of internal leakage in case of stage without shrouds. Lm [kg·s-1] mass flow through stage leaks; δ [m] radial gap length; l [m] blade length.
Loss of uneven velocity distribution in front of cascadeThere is a uneven velocity distribution at the outlet of the blade cascade, which is caused by friction in the boundary layer of the flow at the blade surfaces on both the suction and pressure sides. This non-uniform velocity contour of the working fluid causes the attack angle and velocity, respectively the velocity triangle, to change alternately as the rotor blade cascade moves through such the velocity field, see Figure 14. |
![]() 14: Uneven velocity distribution at stator blade cascade outlet and its effect on velocity triangle S, R-stator or rotor blade cascade; VC-velocity contour in gap between cascades of blades. U [m·s-1] blade speed. The velocity triangle in the core region of the flow is drawn in dashed lines, the velocity triangles in the trailing edge region, where the influence of the boundary layer is fully manifested, are drawn in solid lines.
Loss from incorrect angle of attackLoss from incorrect angle of attack occurs when the working fluid flow direction into the blade passage is incorrect. The angle of attack is then too large or too small compared to the design condition, which can lead to flow separation from the blade.
![]() 15: Change in angle of attack along length of straight blade (a) flow at foot of blades; (b) flow at mean diameter (in core of blade passage); (c) flow at tip of blade. i [°] angle of attack. |
![]() 16: Principle of inlet guide vanes (a) velocity triangle at leading edge of inducer in case of nominal flow; (b) deflection of absolute velocity from axial direction by inlet guide vanes so that inlet angle β1 is kept even at reduced flow. IGV-inlet guide vanes. α [°] absolute velocity angle; β [°] relative velocity angle. Loss through backflowThis type of loss is related to a reduction in the mass flow rate of the stage compared to the nominal state. In the case of reduced flow, significant flow separation from the meridional surfaces of the blade passages (at the foot of the blades) and backflow can occur, as shown in Figure 17. ![]() 17: Flow separation in axial stage from meridional surfaces |
![]() 18: (a) streamline deflection in stage designed for Va(r)=const.; (b) design principle of stage with constant specific mass flow. v [m3·kg-1] specific volume.
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Losses due to change of meridional velocityIt is an effort to make the outlet velocity of the turbomachine the same as the inlet velocity. If the outlet velocity is higher, it means the energy of the working fluid was not transformed into internal work, but remained as kinetic energy, which represents a loss. Of course, there are cases where an increase in outlet velocity is desirable (propellers, jet engines, etc.).
![]() 19: Examples of cone stage performances ε [°] angle between axial direction and direction along conical surface. Further examples of conical stages are shown in the article Thermodynamics of heat turbines. |
![]() 20: Ψ-examined streamline; t [m] length of stage. The figure shows example of flow over purely conical surfaces in turbine stage. The formula is written in the form for the turbine stages, and the same formula applies for the working machine stages, except that it is sufficient to replace index 0 by 1 and index 1 by 3. The derivation of the equation, assuming V0θ=V2θ=0, is shown in Appendix 3.
![]() 21: A [m2] flow area; n-number of flow area. The axial velocity is calculated just in front of the leading edge of the blade and behind the trailing edge of the blade. A change in the radius between the blade cascades causes the outlet triangle of the previous cascade to be different from that of the next cascade, and not only the axial but also the tangential velocity component must be recalculated. The formula is written in the form for the turbine stages, and the same formula applies for the working machine stages, except that it is sufficient to replace index 0 by 1 and index 1 by 3. The derivation of the formula is shown in Appendix 4. |
![]() 22: R [1] reaction. (a) estimate reaction R and from h-s diagram or by calculation determine specific volume at outlet of first blade cascade; (b) calculate axial velocity component; (c) calculate tangential velocity component from constant velocity circulation formula and given triangle on reference radius; (d) calculation of outlet radius of stage according to Formula 20 and angle ε; (e) calculation of radial component of velocity; (f) calculation of absolute velocity; (g) calculation of reaction from velocities; (h) comparison with original estimate of reaction, if the accuracy of the estimate was not sufficient, then calculation is repeated with new estimate. The index ref denotes the entered parameters at the reference radius.
Rotor friction lossRotor friction loss is equivalent to the portion of Euler work that must be expended to overcome the frictional resistance of the working fluid against the rotation of the rotor - so the mean value of Euler work must be greater than the internal work of the stage.
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![]() 23: Occurrence of rotor friction loss between discs (a) main friction surfaces between discs of axial stage; (b) main friction surfaces of radial stages.
![]() 24: wr [J·kg-1] rotor friction loss; qr [J·kg-1] heat from rotor friction loss; δ [1] heat flow distribution coefficient from rotor friction loss; δ·wr [J·kg-1] part of frictional heat transferred to machine walls (heat transferred to surroundings); (1-δ)wr [J·kg-1] part of frictional heat transferred to working fluid.
Losses in inlet of radial stageFor purely radial stages, vortices may form near the leading edges when the flow direction changes from axial to radial Figure 25(a, b). Vortices are also formed at the tips of the radial stage blades Figure 25(d).
![]() 25: Flow reduction for pure radial stage |
Loss due to partial admissionLoss due to partial admission occurs in cases where fluid flows into the stage on only part of the circumference of the rotor blade cascade, see Figure 26. The loss is realized in the marginal zones (swirling of the fluid due to the flow separation from the blades) and by friction of the blades against the stationary working fluid outside the working area. ![]() 26: Partial admission rotor blade cascade in Laval turbine a [m] length of stator blade cascade (nozzle group); l [m] length of blades; FC-flow core; BZ-border zone.
Example of procedure to design stage with lossesWhen deciding on the design procedure for a turbomachine stage, the requirements for its power parameters, price, cost of operation, method of operation and whether it is a machine for series production or piece production are taken into account. For this reason, a universal procedure for calculating turbomachine losses cannot be described. The design of the flow parts of turbomachines can generally be said to be designed according to analytical calculation models and their parameters can be optimised and refined using computer calculation models. |
From the previous sections on losses, it is clear that it is almost impossible to design a turbomachine stage that has the same Euler work respectively losses at all radii. However, for the first iteration, the distribution of Euler work is estimated according to the equation for the irrotational vortex, or Equation 5 for the bowed blades, which were derived for a constant value of Euler work, see Figure 27. Only in later iterations are the losses and work for individual radii calculated more accurately as needed, based on the stage parameters derived from the previous iteration. ![]() 27: wE,is [J·kg-1] Euler work during lossless flow; wE,ref [J·kg-1] proposed linear (constant) Euler work partially respecting mean stage losses; Lw,m [J·kg-1] mean profile stage losses. The figure is drawn for axial stage turbine, the Euler work profile of the working stage is shown in the article Thermodynamics of turbocompressors.
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![]() 28: Reaction of axial stage with constant Euler work and incompressible fluid (a) reaction for case of tangential velocity component proposal according to Formula 5; (b) reaction for case of tangential velocity component proposal according to equation for irrotational vortex (n=-1). The index ref denotes the quantity at the reference radius of the blade. The derivation is shown in Appendix 5. Losses in turbomachine branchesThe branches must keep the fluid pressure uniform around the entire circumference of the inlet part of the first stage and the outlet part of the last stage of the machine. In the inlet branches, the working fluid is usually slightly accelerated towards the first stage. In the outlet branches, the working fluid is usually slightly decelerated towards the last stage. In both cases, the change in velocity compensates for the pressure loss.
![]() 29: Lh,B [J·kg-1] branche loss; Vi [m·s-1] mean velocity in branche inlet section; Lp [Pa] branche pressure loss; ρ [kg·m-3] density; ξB [1] loss coefficient of branche.
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![]() 30: (a) pressure loss in inlet branche (change i-1); (b) pressure loss in outlet branche (change 3-e); (c) h-s chart of single stage working machine with inlet and outlet branche. Index i denotes the working gas state at the inlet, index e denotes the state at the outlet, index 1 denotes the working gas state in front of the rotor, index 2 denotes the state behind the rotor, index 3 denotes the state at the outlet of the stage (rotor+diffuser), index s denotes the stagnation state.
Losses through external leakageThe working fluid can flow through the machine through many paths including leaks and required extractions, then the internal power of the machine is the sum of the internal power on each path, see Figure 31. ![]() 31: Internal power of turbomachine including external leakage wi [J·kg-1] internal work; Pi [W] internal power of machine; m [kg·s-1] mass flow through individual paths (possibly also extractions). x-path number. |
ProblemsProblem 1:
Find the internal losses and internal power of the axial stage of a steam turbine with straight blades. The calculated Euler work efficiency at the mean radius of the stage is 0,8405. The other parameters of the stage are as follows: rm=325 mm; δ=0,5 mm; l=25,6425 mm; α1=20°; U1=102,1018 m·s-1; V1=147,4688 m·s-1; V2=62 m·s-1 (the stage is normal i.e. designed for velocity equality V0=V2); Lh=3,3970 kJ·kg-1 (profile losses); Δhis=21,3 kJ·kg-1, m=12 kg·s-1. The solution of the problem using the models used at PBS is shown in Appendix 1.
![]() (a) meridional section of stage; (b) velocity triangle on mean radius; (c) h-s diagram of stage. ηE [1] Euler work efficiency; l [mm] blade length; α [°] absolute velocity angle; W [m·s-1] relative velocity; h [J·kg-1] enthalpy; s [J·kg-1·K-1] entropy; Lh [kJ·kg-1] profile losses at mean radius; Lw [kJ·kg-1] internal losses; Δhis [kJ·kg-1] isentropic change of enthalpy; m [kg·s-1] mass flow. The index m denotes the mean radius of the blades.
The calculation is carried out in Appendix 1. Problem 2:
Carry out the basic design of the last stage of a steam turbine with twisted blades with constant Euler work along the length of the blades. Carry out the design for a flow with losses, assuming that the value of the profile loss is constant along the length. The given parameters are: p0=13 kPa; h0=2488 kJ·kg-1; ξw=0,1 (relative to the value of Δh); V0=70 m·s-1; p2=3,42 kPa; N=50 s-1; m=52 kg·s-1. Carry out the calculation at least for the foot, the tip of the blade and the mean radius of the blade. The solution to the problem is shown in Appendix 2.
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![]() (a) meridional section of stage; (b) design of shape of velocity triangle; (c) h-s diagram on individual radii with only profile losses.
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©Jiří Škorpík, LICENCE
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